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401706665473 is a prime number
BaseRepresentation
bin1011101100001111001…
…01010100011000000001
31102101212121221221220011
411312013211110120001
523040143401243343
6504312543544521
741010444214051
oct5660745243001
91371777857804
10401706665473
111453a9a38433
1265a2a8bb141
132bb5b0ac779
141562ab01561
15a6b166729d
hex5d87954601

401706665473 has 2 divisors, whose sum is σ = 401706665474. Its totient is φ = 401706665472.

The previous prime is 401706665441. The next prime is 401706665497. The reversal of 401706665473 is 374566607104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 323423102209 + 78283563264 = 568703^2 + 279792^2 .

It is a cyclic number.

It is not a de Polignac number, because 401706665473 - 25 = 401706665441 is a prime.

It is a super-2 number, since 2×4017066654732 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (401706675473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200853332736 + 200853332737.

It is an arithmetic number, because the mean of its divisors is an integer number (200853332737).

Almost surely, 2401706665473 is an apocalyptic number.

It is an amenable number.

401706665473 is a deficient number, since it is larger than the sum of its proper divisors (1).

401706665473 is an equidigital number, since it uses as much as digits as its factorization.

401706665473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 49.

The spelling of 401706665473 in words is "four hundred one billion, seven hundred six million, six hundred sixty-five thousand, four hundred seventy-three".