Base | Representation |
---|---|
bin | 111010011111001101111… |
… | …001011110010100010111 |
3 | 112020020101100201221102021 |
4 | 322133031321132110113 |
5 | 1011322410144124211 |
6 | 12314230054554011 |
7 | 563244506154301 |
oct | 72371571362427 |
9 | 15206340657367 |
10 | 4019248817431 |
11 | 130a6101a3051 |
12 | 54ab5a368907 |
13 | 232023983533 |
14 | dc765966971 |
15 | 6e83ace3771 |
hex | 3a7cde5e517 |
4019248817431 has 2 divisors, whose sum is σ = 4019248817432. Its totient is φ = 4019248817430.
The previous prime is 4019248817413. The next prime is 4019248817471. The reversal of 4019248817431 is 1347188429104.
Together with previous prime (4019248817413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4019248817431 is a prime.
It is a super-2 number, since 2×40192488174312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4019248817471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2009624408715 + 2009624408716.
It is an arithmetic number, because the mean of its divisors is an integer number (2009624408716).
Almost surely, 24019248817431 is an apocalyptic number.
4019248817431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4019248817431 is an equidigital number, since it uses as much as digits as its factorization.
4019248817431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1548288, while the sum is 52.
The spelling of 4019248817431 in words is "four trillion, nineteen billion, two hundred forty-eight million, eight hundred seventeen thousand, four hundred thirty-one".
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