40201234534343 has 2 divisors, whose sum is σ = 40201234534344. Its totient is φ = 40201234534342.

The previous prime is 40201234534319. The next prime is 40201234534399. The reversal of 40201234534343 is 34343543210204.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40201234534343 - 2¹⁶ = 40201234468807 is a prime.

It is a super-3 number, since 3×40201234534343³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 40201234534297 and 40201234534306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40201234524343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20100617267171 + 20100617267172.

It is an arithmetic number, because the mean of its divisors is an integer number (20100617267172).

Almost surely, 2^{40201234534343} is an apocalyptic number.

40201234534343 is a deficient number, since it is larger than the sum of its proper divisors (1).

40201234534343 is an equidigital number, since it uses as much as digits as its factorization.

40201234534343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 38.

Adding to 40201234534343 its reverse (34343543210204), we get a palindrome (74544777744547).

The spelling of 40201234534343 in words is "forty trillion, two hundred one billion, two hundred thirty-four million, five hundred thirty-four thousand, three hundred forty-three".