Base | Representation |
---|---|
bin | 100101011100001011… |
… | …110011001111011001 |
3 | 10211202200211210022012 |
4 | 211130023303033121 |
5 | 1124313013144001 |
6 | 30245045235305 |
7 | 2622140303006 |
oct | 453413631731 |
9 | 124680753265 |
10 | 40201303001 |
11 | 1605a650a62 |
12 | 795b402b35 |
13 | 3a389a4972 |
14 | 1d3520c8ad |
15 | 10a44ec2bb |
hex | 95c2f33d9 |
40201303001 has 2 divisors, whose sum is σ = 40201303002. Its totient is φ = 40201303000.
The previous prime is 40201302971. The next prime is 40201303033. The reversal of 40201303001 is 10030310204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39353037376 + 848265625 = 198376^2 + 29125^2 .
It is a cyclic number.
It is not a de Polignac number, because 40201303001 - 226 = 40134194137 is a prime.
It is a super-2 number, since 2×402013030012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40201303081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20100651500 + 20100651501.
It is an arithmetic number, because the mean of its divisors is an integer number (20100651501).
Almost surely, 240201303001 is an apocalyptic number.
It is an amenable number.
40201303001 is a deficient number, since it is larger than the sum of its proper divisors (1).
40201303001 is an equidigital number, since it uses as much as digits as its factorization.
40201303001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 40201303001 its reverse (10030310204), we get a palindrome (50231613205).
The spelling of 40201303001 in words is "forty billion, two hundred one million, three hundred three thousand, one".
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