Base | Representation |
---|---|
bin | 111010100000000010101… |
… | …000000000001111000011 |
3 | 112020022200000021221000120 |
4 | 322200002220000033003 |
5 | 1011331213124231321 |
6 | 12314453535151323 |
7 | 563305440225303 |
oct | 72400250001703 |
9 | 15208600257016 |
10 | 4020133430211 |
11 | 130aa24575798 |
12 | 54b166675543 |
13 | 232135020252 |
14 | dc80b239603 |
15 | 6e88d7d0ec6 |
hex | 3a802a003c3 |
4020133430211 has 8 divisors (see below), whose sum is σ = 5360284984080. Its totient is φ = 2680035414912.
The previous prime is 4020133430197. The next prime is 4020133430237. The reversal of 4020133430211 is 1120343310204.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4020133430211 - 25 = 4020133430179 is a prime.
It is a super-2 number, since 2×40201334302112 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4020133430251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13209106 + ... + 13510023.
It is an arithmetic number, because the mean of its divisors is an integer number (670035623010).
Almost surely, 24020133430211 is an apocalyptic number.
4020133430211 is a deficient number, since it is larger than the sum of its proper divisors (1340151553869).
4020133430211 is a wasteful number, since it uses less digits than its factorization.
4020133430211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26769285.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 4020133430211 its reverse (1120343310204), we get a palindrome (5140476740415).
The spelling of 4020133430211 in words is "four trillion, twenty billion, one hundred thirty-three million, four hundred thirty thousand, two hundred eleven".
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