Base | Representation |
---|---|
bin | 111010100000000011000… |
… | …010011010100000010001 |
3 | 112020022200111022200001122 |
4 | 322200003002122200101 |
5 | 1011331221412303203 |
6 | 12314454343412025 |
7 | 563305553122052 |
oct | 72400302324021 |
9 | 15208614280048 |
10 | 4020140353553 |
11 | 130aa28474365 |
12 | 54b168a54015 |
13 | 2321365a55bc |
14 | dc80c11c729 |
15 | 6e88e1ec538 |
hex | 3a80309a811 |
4020140353553 has 2 divisors, whose sum is σ = 4020140353554. Its totient is φ = 4020140353552.
The previous prime is 4020140353477. The next prime is 4020140353613. The reversal of 4020140353553 is 3553530410204.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3236573706304 + 783566647249 = 1799048^2 + 885193^2 .
It is a cyclic number.
It is not a de Polignac number, because 4020140353553 - 232 = 4015845386257 is a prime.
It is not a weakly prime, because it can be changed into another prime (4020140359553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010070176776 + 2010070176777.
It is an arithmetic number, because the mean of its divisors is an integer number (2010070176777).
Almost surely, 24020140353553 is an apocalyptic number.
It is an amenable number.
4020140353553 is a deficient number, since it is larger than the sum of its proper divisors (1).
4020140353553 is an equidigital number, since it uses as much as digits as its factorization.
4020140353553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 4020140353553 its reverse (3553530410204), we get a palindrome (7573670763757).
The spelling of 4020140353553 in words is "four trillion, twenty billion, one hundred forty million, three hundred fifty-three thousand, five hundred fifty-three".
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