402033323040131 has 4 divisors (see below), whose sum is σ = 419513032737552. Its totient is φ = 384553613342712.

The previous prime is 402033323040119. The next prime is 402033323040169. The reversal of 402033323040131 is 131040323330204.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 402033323040131 - 2²⁶ = 402033255931267 is a prime.

It is a super-2 number, since 2×402033323040131² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 402033323040094 and 402033323040103.

It is not an unprimeable number, because it can be changed into a prime (402033323040631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8739854848676 + ... + 8739854848721.

It is an arithmetic number, because the mean of its divisors is an integer number (104878258184388).

Almost surely, 2^{402033323040131} is an apocalyptic number.

402033323040131 is a deficient number, since it is larger than the sum of its proper divisors (17479709697421).

402033323040131 is a wasteful number, since it uses less digits than its factorization.

402033323040131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17479709697420.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 402033323040131 its reverse (131040323330204), we get a palindrome (533073646370335).

The spelling of 402033323040131 in words is "four hundred two trillion, thirty-three billion, three hundred twenty-three million, forty thousand, one hundred thirty-one".