Base | Representation |
---|---|
bin | 111010100000111101011… |
… | …011111001110101010001 |
3 | 112020102012202220122201122 |
4 | 322200331123321311101 |
5 | 1011340223222122001 |
6 | 12315135503212025 |
7 | 563342051005364 |
oct | 72407533716521 |
9 | 15212182818648 |
10 | 4021120114001 |
11 | 1310390523941 |
12 | 54b3a0ba7015 |
13 | 232261577303 |
14 | dc8a22bc0db |
15 | 6e8ea231b1b |
hex | 3a83d6f9d51 |
4021120114001 has 4 divisors (see below), whose sum is σ = 4021127073600. Its totient is φ = 4021113154404.
The previous prime is 4021120113971. The next prime is 4021120114027. The reversal of 4021120114001 is 1004110211204.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4021120114001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4021120114031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2525981 + ... + 3797738.
It is an arithmetic number, because the mean of its divisors is an integer number (1005281768400).
Almost surely, 24021120114001 is an apocalyptic number.
It is an amenable number.
4021120114001 is a deficient number, since it is larger than the sum of its proper divisors (6959599).
4021120114001 is an equidigital number, since it uses as much as digits as its factorization.
4021120114001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6959598.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 4021120114001 its reverse (1004110211204), we get a palindrome (5025230325205).
The spelling of 4021120114001 in words is "four trillion, twenty-one billion, one hundred twenty million, one hundred fourteen thousand, one".
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