Base | Representation |
---|---|
bin | 111010100000111110111… |
… | …000010101001010000011 |
3 | 112020102021110111121220022 |
4 | 322200332320111022003 |
5 | 1011340300422440141 |
6 | 12315142130404055 |
7 | 563342463650354 |
oct | 72407670251203 |
9 | 15212243447808 |
10 | 4021144343171 |
11 | 13103a317264a |
12 | 54b3a913062b |
13 | 2322665ab6b7 |
14 | dc8a55c7d2b |
15 | 6e8ec41ab4b |
hex | 3a83ee15283 |
4021144343171 has 2 divisors, whose sum is σ = 4021144343172. Its totient is φ = 4021144343170.
The previous prime is 4021144343159. The next prime is 4021144343189. The reversal of 4021144343171 is 1713434411204.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4021144343171 - 222 = 4021140148867 is a prime.
It is a super-2 number, since 2×40211443431712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4021144343771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010572171585 + 2010572171586.
It is an arithmetic number, because the mean of its divisors is an integer number (2010572171586).
Almost surely, 24021144343171 is an apocalyptic number.
4021144343171 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021144343171 is an equidigital number, since it uses as much as digits as its factorization.
4021144343171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 4021144343171 its reverse (1713434411204), we get a palindrome (5734578754375).
The spelling of 4021144343171 in words is "four trillion, twenty-one billion, one hundred forty-four million, three hundred forty-three thousand, one hundred seventy-one".
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