Base | Representation |
---|---|
bin | 10010010010010100111010… |
… | …11001000111101001111111 |
3 | 12021101020112002110201011211 |
4 | 21021022131121013221333 |
5 | 20232313412323324043 |
6 | 221305110035025251 |
7 | 11320141634010664 |
oct | 1111123531075177 |
9 | 167336462421154 |
10 | 40212124433023 |
11 | 118a3958a07254 |
12 | 461546713b227 |
13 | 1958caa76805a |
14 | 9d03c4929a6b |
15 | 49b0227e0a9d |
hex | 24929d647a7f |
40212124433023 has 2 divisors, whose sum is σ = 40212124433024. Its totient is φ = 40212124433022.
The previous prime is 40212124432999. The next prime is 40212124433051. The reversal of 40212124433023 is 32033442121204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40212124433023 - 213 = 40212124424831 is a prime.
It is a super-3 number, since 3×402121244330233 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40212124433093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20106062216511 + 20106062216512.
It is an arithmetic number, because the mean of its divisors is an integer number (20106062216512).
Almost surely, 240212124433023 is an apocalyptic number.
40212124433023 is a deficient number, since it is larger than the sum of its proper divisors (1).
40212124433023 is an equidigital number, since it uses as much as digits as its factorization.
40212124433023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 40212124433023 its reverse (32033442121204), we get a palindrome (72245566554227).
The spelling of 40212124433023 in words is "forty trillion, two hundred twelve billion, one hundred twenty-four million, four hundred thirty-three thousand, twenty-three".
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