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40212131 is a prime number
BaseRepresentation
bin1001100101100…
…1011010100011
32210122222200012
42121121122203
540243242011
63553515135
7665540351
oct231313243
983588605
1040212131
1120775a73
1211572aab
13843c27b
1454aa7d1
1537e4a8b
hex26596a3

40212131 has 2 divisors, whose sum is σ = 40212132. Its totient is φ = 40212130.

The previous prime is 40212121. The next prime is 40212143. The reversal of 40212131 is 13121204.

40212131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40212131 is a prime.

It is a super-2 number, since 2×402121312 = 3234030959122322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (40212101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20106065 + 20106066.

It is an arithmetic number, because the mean of its divisors is an integer number (20106066).

Almost surely, 240212131 is an apocalyptic number.

40212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40212131 is an equidigital number, since it uses as much as digits as its factorization.

40212131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 40212131 is about 6341.3035726103. The cubic root of 40212131 is about 342.5986885944.

Adding to 40212131 its reverse (13121204), we get a palindrome (53333335).

The spelling of 40212131 in words is "forty million, two hundred twelve thousand, one hundred thirty-one".