4021301012131 has 8 divisors (see below), whose sum is σ = 4436257027104. Its totient is φ = 3621434306880.

The previous prime is 4021301012123. The next prime is 4021301012177. The reversal of 4021301012131 is 1312101031204.

4021301012131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 4021301012131 - 2³ = 4021301012123 is a prime.

It is a super-2 number, since 2×4021301012131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4021301012099 and 4021301012108.

It is not an unprimeable number, because it can be changed into a prime (4021301012101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3772326871 + ... + 3772327936.

It is an arithmetic number, because the mean of its divisors is an integer number (554532128388).

Almost surely, 2^{4021301012131} is an apocalyptic number.

4021301012131 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

4021301012131 is a deficient number, since it is larger than the sum of its proper divisors (414956014973).

4021301012131 is a wasteful number, since it uses less digits than its factorization.

4021301012131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7544654861.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 4021301012131 its reverse (1312101031204), we get a palindrome (5333402043335).

The spelling of 4021301012131 in words is "four trillion, twenty-one billion, three hundred one million, twelve thousand, one hundred thirty-one".