Base | Representation |
---|---|
bin | 111010100001001010101… |
… | …110100111001111100011 |
3 | 112020102210022112122202002 |
4 | 322201022232213033203 |
5 | 1011341202314404103 |
6 | 12315213551114215 |
7 | 563350426361555 |
oct | 72411256471743 |
9 | 15212708478662 |
10 | 4021343122403 |
11 | 13104953a1402 |
12 | 54b44381296b |
13 | 232298829149 |
14 | dc8c3b6d4d5 |
15 | 6e90ead3488 |
hex | 3a84aba73e3 |
4021343122403 has 2 divisors, whose sum is σ = 4021343122404. Its totient is φ = 4021343122402.
The previous prime is 4021343122387. The next prime is 4021343122439. The reversal of 4021343122403 is 3042213431204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4021343122403 - 24 = 4021343122387 is a prime.
It is not a weakly prime, because it can be changed into another prime (4021343122103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010671561201 + 2010671561202.
It is an arithmetic number, because the mean of its divisors is an integer number (2010671561202).
Almost surely, 24021343122403 is an apocalyptic number.
4021343122403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021343122403 is an equidigital number, since it uses as much as digits as its factorization.
4021343122403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 4021343122403 its reverse (3042213431204), we get a palindrome (7063556553607).
The spelling of 4021343122403 in words is "four trillion, twenty-one billion, three hundred forty-three million, one hundred twenty-two thousand, four hundred three".
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