4021424322131 has 2 divisors, whose sum is σ = 4021424322132. Its totient is φ = 4021424322130.

The previous prime is 4021424322127. The next prime is 4021424322133. The reversal of 4021424322131 is 1312234241204.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4021424322131 - 2² = 4021424322127 is a prime.

It is a super-2 number, since 2×4021424322131² (a number of 26 digits) contains 22 as substring.

Together with 4021424322133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4021424322094 and 4021424322103.

It is not a weakly prime, because it can be changed into another prime (4021424322133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010712161065 + 2010712161066.

It is an arithmetic number, because the mean of its divisors is an integer number (2010712161066).

Almost surely, 2^{4021424322131} is an apocalyptic number.

4021424322131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4021424322131 is an equidigital number, since it uses as much as digits as its factorization.

4021424322131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 4021424322131 its reverse (1312234241204), we get a palindrome (5333658563335).

The spelling of 4021424322131 in words is "four trillion, twenty-one billion, four hundred twenty-four million, three hundred twenty-two thousand, one hundred thirty-one".