Base | Representation |
---|---|
bin | 111010100001010000000… |
… | …011001110110001111111 |
3 | 112020110000112120002211202 |
4 | 322201100003032301333 |
5 | 1011341343144211221 |
6 | 12315230501010115 |
7 | 563352562342115 |
oct | 72412003166177 |
9 | 15213015502752 |
10 | 4021432413311 |
11 | 1310530838a45 |
12 | 54b4696b393b |
13 | 2322b11903c1 |
14 | dc8d1973ab5 |
15 | 6e91786ed0b |
hex | 3a8500cec7f |
4021432413311 has 2 divisors, whose sum is σ = 4021432413312. Its totient is φ = 4021432413310.
The previous prime is 4021432413281. The next prime is 4021432413343. The reversal of 4021432413311 is 1133142341204.
4021432413311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4021432413311 - 238 = 3746554506367 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4021432413211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010716206655 + 2010716206656.
It is an arithmetic number, because the mean of its divisors is an integer number (2010716206656).
Almost surely, 24021432413311 is an apocalyptic number.
4021432413311 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021432413311 is an equidigital number, since it uses as much as digits as its factorization.
4021432413311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 4021432413311 its reverse (1133142341204), we get a palindrome (5154574754515).
The spelling of 4021432413311 in words is "four trillion, twenty-one billion, four hundred thirty-two million, four hundred thirteen thousand, three hundred eleven".
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