Base | Representation |
---|---|
bin | 111010100001010000000… |
… | …101100011111010000011 |
3 | 112020110000120201010201201 |
4 | 322201100011203322003 |
5 | 1011341343323233011 |
6 | 12315230522042031 |
7 | 563352600464665 |
oct | 72412005437203 |
9 | 15213016633651 |
10 | 4021433024131 |
11 | 1310531115956 |
12 | 54b469949317 |
13 | 2322b1345433 |
14 | dc8d1a92535 |
15 | 6e917940cc1 |
hex | 3a850163e83 |
4021433024131 has 2 divisors, whose sum is σ = 4021433024132. Its totient is φ = 4021433024130.
The previous prime is 4021433024111. The next prime is 4021433024137. The reversal of 4021433024131 is 1314203341204.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4021433024131 - 25 = 4021433024099 is a prime.
It is a super-2 number, since 2×40214330241312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4021433024131.
It is not a weakly prime, because it can be changed into another prime (4021433024137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010716512065 + 2010716512066.
It is an arithmetic number, because the mean of its divisors is an integer number (2010716512066).
Almost surely, 24021433024131 is an apocalyptic number.
4021433024131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021433024131 is an equidigital number, since it uses as much as digits as its factorization.
4021433024131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 4021433024131 its reverse (1314203341204), we get a palindrome (5335636365335).
The spelling of 4021433024131 in words is "four trillion, twenty-one billion, four hundred thirty-three million, twenty-four thousand, one hundred thirty-one".
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