Base | Representation |
---|---|
bin | 111010100001010000101… |
… | …001010111010111111111 |
3 | 112020110001020100222200212 |
4 | 322201100221113113333 |
5 | 1011341403224104413 |
6 | 12315231455143035 |
7 | 563353043325665 |
oct | 72412051272777 |
9 | 15213036328625 |
10 | 4021442409983 |
11 | 1310536446659 |
12 | 54b470b14a7b |
13 | 2322b32805ab |
14 | dc8d3016c35 |
15 | 6e918696ca8 |
hex | 3a850a575ff |
4021442409983 has 2 divisors, whose sum is σ = 4021442409984. Its totient is φ = 4021442409982.
The previous prime is 4021442409893. The next prime is 4021442409997. The reversal of 4021442409983 is 3899042441204.
Together with previous prime (4021442409893) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4021442409983 - 28 = 4021442409727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4021442402983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010721204991 + 2010721204992.
It is an arithmetic number, because the mean of its divisors is an integer number (2010721204992).
Almost surely, 24021442409983 is an apocalyptic number.
4021442409983 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021442409983 is an equidigital number, since it uses as much as digits as its factorization.
4021442409983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1990656, while the sum is 50.
The spelling of 4021442409983 in words is "four trillion, twenty-one billion, four hundred forty-two million, four hundred nine thousand, nine hundred eighty-three".
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