4022000000113 has 4 divisors (see below), whose sum is σ = 4022077411648. Its totient is φ = 4021922588580.

The previous prime is 4022000000101. The next prime is 4022000000167. The reversal of 4022000000113 is 3110000002204.

4022000000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4022000000113 - 2²¹ = 4021997902961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4022000000093 and 4022000000102.

It is not an unprimeable number, because it can be changed into a prime (4022000600113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38627781 + ... + 38731762.

It is an arithmetic number, because the mean of its divisors is an integer number (1005519352912).

Almost surely, 2^{4022000000113} is an apocalyptic number.

It is an amenable number.

4022000000113 is a deficient number, since it is larger than the sum of its proper divisors (77411535).

4022000000113 is an equidigital number, since it uses as much as digits as its factorization.

4022000000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77411534.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 4022000000113 its reverse (3110000002204), we get a palindrome (7132000002317).

The spelling of 4022000000113 in words is "four trillion, twenty-two billion, one hundred thirteen", and thus it is an aban number.