Base | Representation |
---|---|
bin | 111010100001110001111… |
… | …000011001110010000011 |
3 | 112020111111002120111120211 |
4 | 322201301320121302003 |
5 | 1011344024000001011 |
6 | 12315403054214551 |
7 | 563402623632151 |
oct | 72416170316203 |
9 | 15214432514524 |
10 | 4022000000131 |
11 | 13107a2168363 |
12 | 54b5a77b4457 |
13 | 23237194a7a9 |
14 | dc9470c03d1 |
15 | 6e94c5d8b21 |
hex | 3a871e19c83 |
4022000000131 has 4 divisors (see below), whose sum is σ = 4022004963232. Its totient is φ = 4021995037032.
The previous prime is 4022000000101. The next prime is 4022000000167. The reversal of 4022000000131 is 1310000002204.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 4022000000131 - 219 = 4021999475843 is a prime.
It is a super-2 number, since 2×40220000001312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4022000000101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 951531 + ... + 2991556.
It is an arithmetic number, because the mean of its divisors is an integer number (1005501240808).
Almost surely, 24022000000131 is an apocalyptic number.
4022000000131 is a deficient number, since it is larger than the sum of its proper divisors (4963101).
4022000000131 is a wasteful number, since it uses less digits than its factorization.
4022000000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4963100.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 4022000000131 its reverse (1310000002204), we get a palindrome (5332000002335).
The spelling of 4022000000131 in words is "four trillion, twenty-two billion, one hundred thirty-one", and thus it is an aban number.
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