Base | Representation |
---|---|
bin | 111010100001110011001… |
… | …101111001110001101001 |
3 | 112020111112122202012211112 |
4 | 322201303031321301221 |
5 | 1011344100214212132 |
6 | 12315405214440105 |
7 | 563403315302051 |
oct | 72416315716151 |
9 | 15214478665745 |
10 | 4022022413417 |
11 | 1310803886838 |
12 | 54b5b3203035 |
13 | 2323764974a8 |
14 | dc94a076561 |
15 | 6e94e564ab2 |
hex | 3a873379c69 |
4022022413417 has 2 divisors, whose sum is σ = 4022022413418. Its totient is φ = 4022022413416.
The previous prime is 4022022413377. The next prime is 4022022413441. The reversal of 4022022413417 is 7143142202204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2767418565136 + 1254603848281 = 1663556^2 + 1120091^2 .
It is a cyclic number.
It is not a de Polignac number, because 4022022413417 - 226 = 4021955304553 is a prime.
It is not a weakly prime, because it can be changed into another prime (4022022413447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011011206708 + 2011011206709.
It is an arithmetic number, because the mean of its divisors is an integer number (2011011206709).
Almost surely, 24022022413417 is an apocalyptic number.
It is an amenable number.
4022022413417 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022022413417 is an equidigital number, since it uses as much as digits as its factorization.
4022022413417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
The spelling of 4022022413417 in words is "four trillion, twenty-two billion, twenty-two million, four hundred thirteen thousand, four hundred seventeen".
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