Base | Representation |
---|---|
bin | 1011101101001011010… |
… | …01101111110111011011 |
3 | 1102110011210020002010212 |
4 | 11312211221233313123 |
5 | 23042212023040011 |
6 | 504435004401335 |
7 | 41026111210310 |
oct | 5664551576733 |
9 | 1373153202125 |
10 | 402211143131 |
11 | 145638782a16 |
12 | 65b4b84624b |
13 | 2bc0b771965 |
14 | 15677b00d07 |
15 | a6e0ab708b |
hex | 5da5a6fddb |
402211143131 has 4 divisors (see below), whose sum is σ = 459669877872. Its totient is φ = 344752408392.
The previous prime is 402211143101. The next prime is 402211143149. The reversal of 402211143131 is 131341112204.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 402211143131 - 210 = 402211142107 is a prime.
It is a super-2 number, since 2×4022111431312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 402211143097 and 402211143106.
It is not an unprimeable number, because it can be changed into a prime (402211143101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28729367360 + ... + 28729367373.
It is an arithmetic number, because the mean of its divisors is an integer number (114917469468).
Almost surely, 2402211143131 is an apocalyptic number.
402211143131 is a deficient number, since it is larger than the sum of its proper divisors (57458734741).
402211143131 is an equidigital number, since it uses as much as digits as its factorization.
402211143131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57458734740.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 402211143131 its reverse (131341112204), we get a palindrome (533552255335).
The spelling of 402211143131 in words is "four hundred two billion, two hundred eleven million, one hundred forty-three thousand, one hundred thirty-one".
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