Base | Representation |
---|---|
bin | 111010100001111001010… |
… | …011000000010011011101 |
3 | 112020111210202200101120022 |
4 | 322201321103000103131 |
5 | 1011344302322223143 |
6 | 12315423301001525 |
7 | 563405664266255 |
oct | 72417123002335 |
9 | 15214722611508 |
10 | 4022124414173 |
11 | 1310856414488 |
12 | 54b6213b32a5 |
13 | 23239165b878 |
14 | dc959828965 |
15 | 6e9584b2268 |
hex | 3a8794c04dd |
4022124414173 has 2 divisors, whose sum is σ = 4022124414174. Its totient is φ = 4022124414172.
The previous prime is 4022124414131. The next prime is 4022124414181. The reversal of 4022124414173 is 3714144212204.
4022124414173 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3441629756569 + 580494657604 = 1855163^2 + 761902^2 .
It is a cyclic number.
It is not a de Polignac number, because 4022124414173 - 214 = 4022124397789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4022124714173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011062207086 + 2011062207087.
It is an arithmetic number, because the mean of its divisors is an integer number (2011062207087).
Almost surely, 24022124414173 is an apocalyptic number.
It is an amenable number.
4022124414173 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022124414173 is an equidigital number, since it uses as much as digits as its factorization.
4022124414173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 4022124414173 its reverse (3714144212204), we get a palindrome (7736268626377).
The spelling of 4022124414173 in words is "four trillion, twenty-two billion, one hundred twenty-four million, four hundred fourteen thousand, one hundred seventy-three".
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