Base | Representation |
---|---|
bin | 111010100001111111110… |
… | …110010011100100001111 |
3 | 112020112002102111202122222 |
4 | 322201333312103210033 |
5 | 1011400013442101112 |
6 | 12315442224525555 |
7 | 563411500464545 |
oct | 72417766234417 |
9 | 15215072452588 |
10 | 4022234331407 |
11 | 1310902469976 |
12 | 54b6521808bb |
13 | 2323ab365356 |
14 | dc96a27bd95 |
15 | 6e962e75372 |
hex | 3a87fd9390f |
4022234331407 has 2 divisors, whose sum is σ = 4022234331408. Its totient is φ = 4022234331406.
The previous prime is 4022234331281. The next prime is 4022234331413. The reversal of 4022234331407 is 7041334322204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4022234331407 - 210 = 4022234330383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4022234331607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011117165703 + 2011117165704.
It is an arithmetic number, because the mean of its divisors is an integer number (2011117165704).
Almost surely, 24022234331407 is an apocalyptic number.
4022234331407 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022234331407 is an equidigital number, since it uses as much as digits as its factorization.
4022234331407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 4022234331407 in words is "four trillion, twenty-two billion, two hundred thirty-four million, three hundred thirty-one thousand, four hundred seven".
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