Base | Representation |
---|---|
bin | 111010100010001011000… |
… | …011110001100000111111 |
3 | 112020112120112102012210221 |
4 | 322202023003301200333 |
5 | 1011400410114130302 |
6 | 12315513024042211 |
7 | 563416243234525 |
oct | 72421303614077 |
9 | 15215515365727 |
10 | 4022422411327 |
11 | 1310999650121 |
12 | 54b6a5163367 |
13 | 23240b307b48 |
14 | dc98723a315 |
15 | 6e974727937 |
hex | 3a88b0f183f |
4022422411327 has 2 divisors, whose sum is σ = 4022422411328. Its totient is φ = 4022422411326.
The previous prime is 4022422411303. The next prime is 4022422411333. The reversal of 4022422411327 is 7231142242204.
4022422411327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4022422411327 - 219 = 4022421887039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4022422411292 and 4022422411301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4022422414327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011211205663 + 2011211205664.
It is an arithmetic number, because the mean of its divisors is an integer number (2011211205664).
Almost surely, 24022422411327 is an apocalyptic number.
4022422411327 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022422411327 is an equidigital number, since it uses as much as digits as its factorization.
4022422411327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43008, while the sum is 34.
The spelling of 4022422411327 in words is "four trillion, twenty-two billion, four hundred twenty-two million, four hundred eleven thousand, three hundred twenty-seven".
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