Base | Representation |
---|---|
bin | 111010100010001011001… |
… | …010010010111100100111 |
3 | 112020112120122122002012212 |
4 | 322202023022102330213 |
5 | 1011400411033334002 |
6 | 12315513124434035 |
7 | 563416263615416 |
oct | 72421312227447 |
9 | 15215518562185 |
10 | 4022424121127 |
11 | 131099a608785 |
12 | 54b6a584891b |
13 | 23240b786169 |
14 | dc98756347d |
15 | 6e974964352 |
hex | 3a88b292f27 |
4022424121127 has 2 divisors, whose sum is σ = 4022424121128. Its totient is φ = 4022424121126.
The previous prime is 4022424121057. The next prime is 4022424121211. The reversal of 4022424121127 is 7211214242204.
4022424121127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4022424121127 - 218 = 4022423858983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4022424121093 and 4022424121102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4022424111127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011212060563 + 2011212060564.
It is an arithmetic number, because the mean of its divisors is an integer number (2011212060564).
Almost surely, 24022424121127 is an apocalyptic number.
4022424121127 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022424121127 is an equidigital number, since it uses as much as digits as its factorization.
4022424121127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14336, while the sum is 32.
The spelling of 4022424121127 in words is "four trillion, twenty-two billion, four hundred twenty-four million, one hundred twenty-one thousand, one hundred twenty-seven".
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