Base | Representation |
---|---|
bin | 111010100010101101101… |
… | …011101110100101000011 |
3 | 112020121002000110221112112 |
4 | 322202231223232211003 |
5 | 1011403102321413103 |
6 | 12320050414445535 |
7 | 563436525631040 |
oct | 72425553564503 |
9 | 15217060427475 |
10 | 4023003310403 |
11 | 1311167542200 |
12 | 54b8278038ab |
13 | 2324a17765cc |
14 | dca004501c7 |
15 | 6e9aa720cd8 |
hex | 3a8adaee943 |
4023003310403 has 96 divisors (see below), whose sum is σ = 5464809208320. Its totient is φ = 2889337651200.
The previous prime is 4023003310373. The next prime is 4023003310421. The reversal of 4023003310403 is 3040133003204.
It is not a de Polignac number, because 4023003310403 - 210 = 4023003309379 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4023003312403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 177832433 + ... + 177855053.
It is an arithmetic number, because the mean of its divisors is an integer number (56925095920).
Almost surely, 24023003310403 is an apocalyptic number.
4023003310403 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
4023003310403 is a deficient number, since it is larger than the sum of its proper divisors (1441805897917).
4023003310403 is a wasteful number, since it uses less digits than its factorization.
4023003310403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22969 (or 22958 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 4023003310403 its reverse (3040133003204), we get a palindrome (7063136313607).
The spelling of 4023003310403 in words is "four trillion, twenty-three billion, three million, three hundred ten thousand, four hundred three".
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