Base | Representation |
---|---|
bin | 10010010010111000111000… |
… | …00110000000110110010001 |
3 | 12021110002100112022010102121 |
4 | 21021130130012000312101 |
5 | 20233122432040000032 |
6 | 221322021440214241 |
7 | 11321424224430604 |
oct | 1111343406006621 |
9 | 167402315263377 |
10 | 40231430000017 |
11 | 119010654494a3 |
12 | 461915460a381 |
13 | 195aa66302489 |
14 | 9d12d68c633b |
15 | 49b7a25d8a97 |
hex | 24971c180d91 |
40231430000017 has 2 divisors, whose sum is σ = 40231430000018. Its totient is φ = 40231430000016.
The previous prime is 40231429999987. The next prime is 40231430000057. The reversal of 40231430000017 is 71000003413204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26998997955136 + 13232432044881 = 5196056^2 + 3637641^2 .
It is a cyclic number.
It is not a de Polignac number, because 40231430000017 - 215 = 40231429967249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40231429999946 and 40231430000000.
It is not a weakly prime, because it can be changed into another prime (40231430000057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20115715000008 + 20115715000009.
It is an arithmetic number, because the mean of its divisors is an integer number (20115715000009).
Almost surely, 240231430000017 is an apocalyptic number.
It is an amenable number.
40231430000017 is a deficient number, since it is larger than the sum of its proper divisors (1).
40231430000017 is an equidigital number, since it uses as much as digits as its factorization.
40231430000017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 40231430000017 in words is "forty trillion, two hundred thirty-one billion, four hundred thirty million, seventeen", and thus it is an aban number.
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