Base | Representation |
---|---|
bin | 100101011110000001… |
… | …010100100101100001 |
3 | 10211211211210222011012 |
4 | 211132001110211201 |
5 | 1124343410013213 |
6 | 30252105430305 |
7 | 2622663203414 |
oct | 453601244541 |
9 | 124754728135 |
10 | 40232110433 |
11 | 16075a83049 |
12 | 796979b395 |
13 | 3a421a0308 |
14 | 1d3934bb7b |
15 | 10a70854a8 |
hex | 95e054961 |
40232110433 has 4 divisors (see below), whose sum is σ = 40248883200. Its totient is φ = 40215337668.
The previous prime is 40232110421. The next prime is 40232110463. The reversal of 40232110433 is 33401123204.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40232110433 - 224 = 40215333217 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40232110399 and 40232110408.
It is not an unprimeable number, because it can be changed into a prime (40232110463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8382785 + ... + 8387582.
It is an arithmetic number, because the mean of its divisors is an integer number (10062220800).
Almost surely, 240232110433 is an apocalyptic number.
It is an amenable number.
40232110433 is a deficient number, since it is larger than the sum of its proper divisors (16772767).
40232110433 is a wasteful number, since it uses less digits than its factorization.
40232110433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16772766.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 40232110433 its reverse (33401123204), we get a palindrome (73633233637).
The spelling of 40232110433 in words is "forty billion, two hundred thirty-two million, one hundred ten thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •