Base | Representation |
---|---|
bin | 111010100010111011010… |
… | …100000011111011101001 |
3 | 112020121122221202221110011 |
4 | 322202323110003323221 |
5 | 1011404034342044213 |
6 | 12320125224051521 |
7 | 563445303433651 |
oct | 72427324037351 |
9 | 15217587687404 |
10 | 4023231987433 |
11 | 131127463168a |
12 | 54b890303ba1 |
13 | 232509c61669 |
14 | dca22979361 |
15 | 6e9c084203d |
hex | 3a8bb503ee9 |
4023231987433 has 2 divisors, whose sum is σ = 4023231987434. Its totient is φ = 4023231987432.
The previous prime is 4023231987421. The next prime is 4023231987479. The reversal of 4023231987433 is 3347891323204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3151040363689 + 872191623744 = 1775117^2 + 933912^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4023231987433 is a prime.
It is not a weakly prime, because it can be changed into another prime (4023231984433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011615993716 + 2011615993717.
It is an arithmetic number, because the mean of its divisors is an integer number (2011615993717).
Almost surely, 24023231987433 is an apocalyptic number.
It is an amenable number.
4023231987433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023231987433 is an equidigital number, since it uses as much as digits as its factorization.
4023231987433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2612736, while the sum is 49.
The spelling of 4023231987433 in words is "four trillion, twenty-three billion, two hundred thirty-one million, nine hundred eighty-seven thousand, four hundred thirty-three".
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