Base | Representation |
---|---|
bin | 10010010010111011111111… |
… | …10001000001111111111111 |
3 | 12021110020200001212202210121 |
4 | 21021131333301001333333 |
5 | 20233134343132040221 |
6 | 221322455413515411 |
7 | 11321513531165416 |
oct | 1111357761017777 |
9 | 167406601782717 |
10 | 40233102221311 |
11 | 1190184336906a |
12 | 4619540642b67 |
13 | 195ac718a3b2c |
14 | 9d1414a1a47d |
15 | 49b84e301a41 |
hex | 24977fc41fff |
40233102221311 has 4 divisors (see below), whose sum is σ = 41620450573800. Its totient is φ = 38845753868824.
The previous prime is 40233102221269. The next prime is 40233102221317. The reversal of 40233102221311 is 11312220133204.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40233102221311 - 213 = 40233102213119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40233102221317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 693674176201 + ... + 693674176258.
It is an arithmetic number, because the mean of its divisors is an integer number (10405112643450).
Almost surely, 240233102221311 is an apocalyptic number.
40233102221311 is a deficient number, since it is larger than the sum of its proper divisors (1387348352489).
40233102221311 is a wasteful number, since it uses less digits than its factorization.
40233102221311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1387348352488.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 40233102221311 its reverse (11312220133204), we get a palindrome (51545322354515).
The spelling of 40233102221311 in words is "forty trillion, two hundred thirty-three billion, one hundred two million, two hundred twenty-one thousand, three hundred eleven".
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