Base | Representation |
---|---|
bin | 111010100011000000000… |
… | …110001100111011011011 |
3 | 112020121212112210012202022 |
4 | 322203000012030323123 |
5 | 1011404220413142342 |
6 | 12320141212125055 |
7 | 563450266532321 |
oct | 72430006147333 |
9 | 15217775705668 |
10 | 4023312240347 |
11 | 1311305965904 |
12 | 54b8b316678b |
13 | 23252077cbaa |
14 | dca2d4a9d11 |
15 | 6e9c78e59d2 |
hex | 3a8c018cedb |
4023312240347 has 2 divisors, whose sum is σ = 4023312240348. Its totient is φ = 4023312240346.
The previous prime is 4023312240329. The next prime is 4023312240349. The reversal of 4023312240347 is 7430422133204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4023312240347 is a prime.
Together with 4023312240349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4023312240349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011656120173 + 2011656120174.
It is an arithmetic number, because the mean of its divisors is an integer number (2011656120174).
Almost surely, 24023312240347 is an apocalyptic number.
4023312240347 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023312240347 is an equidigital number, since it uses as much as digits as its factorization.
4023312240347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 4023312240347 in words is "four trillion, twenty-three billion, three hundred twelve million, two hundred forty thousand, three hundred forty-seven".
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