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40234213303 = 367109630009
BaseRepresentation
bin100101011110001001…
…010101111110110111
310211211222202210202021
4211132021111332313
51124344424311203
630252222454011
72623020112264
oct453611257667
9124758683667
1040234213303
1116077189a59
12796a434307
133a4275850b
141d3973826b
1510a734d5bd
hex95e255fb7

40234213303 has 4 divisors (see below), whose sum is σ = 40343843680. Its totient is φ = 40124582928.

The previous prime is 40234213289. The next prime is 40234213337. The reversal of 40234213303 is 30331243204.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40234213303 - 213 = 40234205111 is a prime.

It is a super-2 number, since 2×402342133032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40234213373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54814638 + ... + 54815371.

It is an arithmetic number, because the mean of its divisors is an integer number (10085960920).

Almost surely, 240234213303 is an apocalyptic number.

40234213303 is a deficient number, since it is larger than the sum of its proper divisors (109630377).

40234213303 is a wasteful number, since it uses less digits than its factorization.

40234213303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109630376.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 40234213303 its reverse (30331243204), we get a palindrome (70565456507).

The spelling of 40234213303 in words is "forty billion, two hundred thirty-four million, two hundred thirteen thousand, three hundred three".

Divisors: 1 367 109630009 40234213303