Base | Representation |
---|---|
bin | 111010100011000110110… |
… | …001010011001011011011 |
3 | 112020122011100110102111021 |
4 | 322203012301103023123 |
5 | 1011404433043421220 |
6 | 12320200251543311 |
7 | 563453126302432 |
oct | 72430661231333 |
9 | 15218140412437 |
10 | 4023424201435 |
11 | 1311363086931 |
12 | 54b92475ab37 |
13 | 23253aa20a62 |
14 | dca402d2119 |
15 | 6e9d265e4aa |
hex | 3a8c6c532db |
4023424201435 has 4 divisors (see below), whose sum is σ = 4828109041728. Its totient is φ = 3218739361144.
The previous prime is 4023424201417. The next prime is 4023424201451. The reversal of 4023424201435 is 5341024243204.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4023424201435 - 215 = 4023424168667 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 4023424201435.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402342420139 + ... + 402342420148.
It is an arithmetic number, because the mean of its divisors is an integer number (1207027260432).
Almost surely, 24023424201435 is an apocalyptic number.
4023424201435 is a deficient number, since it is larger than the sum of its proper divisors (804684840293).
4023424201435 is an equidigital number, since it uses as much as digits as its factorization.
4023424201435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 804684840292.
The product of its (nonzero) digits is 92160, while the sum is 34.
Adding to 4023424201435 its reverse (5341024243204), we get a palindrome (9364448444639).
The spelling of 4023424201435 in words is "four trillion, twenty-three billion, four hundred twenty-four million, two hundred one thousand, four hundred thirty-five".
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