Base | Representation |
---|---|
bin | 10010010011001001000011… |
… | …01001100000010010111111 |
3 | 12021110220202200010120000021 |
4 | 21021210201221200102333 |
5 | 20233243222424441133 |
6 | 221330015221513011 |
7 | 11322152341655503 |
oct | 1111444151402277 |
9 | 167426680116007 |
10 | 40240113124543 |
11 | 1190481088a472 |
12 | 461a978572767 |
13 | 195b81b226797 |
14 | 9d18bbbb4303 |
15 | 49bb0ea7152d |
hex | 249921a604bf |
40240113124543 has 2 divisors, whose sum is σ = 40240113124544. Its totient is φ = 40240113124542.
The previous prime is 40240113124441. The next prime is 40240113124553. The reversal of 40240113124543 is 34542131104204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40240113124543 is a prime.
It is a super-3 number, since 3×402401131245433 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40240113124499 and 40240113124508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40240113124553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20120056562271 + 20120056562272.
It is an arithmetic number, because the mean of its divisors is an integer number (20120056562272).
Almost surely, 240240113124543 is an apocalyptic number.
40240113124543 is a deficient number, since it is larger than the sum of its proper divisors (1).
40240113124543 is an equidigital number, since it uses as much as digits as its factorization.
40240113124543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 40240113124543 its reverse (34542131104204), we get a palindrome (74782244228747).
The spelling of 40240113124543 in words is "forty trillion, two hundred forty billion, one hundred thirteen million, one hundred twenty-four thousand, five hundred forty-three".
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