Base | Representation |
---|---|
bin | 100101011110100100… |
… | …100010011000101001 |
3 | 10211212111011222110211 |
4 | 211132210202120221 |
5 | 1124403240420433 |
6 | 30253035341121 |
7 | 2623134522526 |
oct | 453644423051 |
9 | 124774158424 |
10 | 40241341993 |
11 | 16080208936 |
12 | 79708b17a1 |
13 | 3a44083188 |
14 | 1d3a67214d |
15 | 10a7caa8cd |
hex | 95e922629 |
40241341993 has 2 divisors, whose sum is σ = 40241341994. Its totient is φ = 40241341992.
The previous prime is 40241341979. The next prime is 40241342033. The reversal of 40241341993 is 39914314204.
It is an a-pointer prime, because the next prime (40241342033) can be obtained adding 40241341993 to its sum of digits (40).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38387781184 + 1853560809 = 195928^2 + 43053^2 .
It is a cyclic number.
It is not a de Polignac number, because 40241341993 - 25 = 40241341961 is a prime.
It is not a weakly prime, because it can be changed into another prime (40241345993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20120670996 + 20120670997.
It is an arithmetic number, because the mean of its divisors is an integer number (20120670997).
Almost surely, 240241341993 is an apocalyptic number.
It is an amenable number.
40241341993 is a deficient number, since it is larger than the sum of its proper divisors (1).
40241341993 is an equidigital number, since it uses as much as digits as its factorization.
40241341993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 40.
The spelling of 40241341993 in words is "forty billion, two hundred forty-one million, three hundred forty-one thousand, nine hundred ninety-three".
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