Base | Representation |
---|---|
bin | 100101011110100111… |
… | …000110001111001011 |
3 | 10211212112110002002210 |
4 | 211132213012033023 |
5 | 1124403423410011 |
6 | 30253102000203 |
7 | 2623143316305 |
oct | 453647061713 |
9 | 124775402083 |
10 | 40242013131 |
11 | 160806270a1 |
12 | 7970b76063 |
13 | 3a442597b8 |
14 | 1d3a7a8975 |
15 | 10a7d8e6a6 |
hex | 95e9c63cb |
40242013131 has 8 divisors (see below), whose sum is σ = 56812253904. Its totient is φ = 25249890560.
The previous prime is 40242013117. The next prime is 40242013159. The reversal of 40242013131 is 13131024204.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 40242013131 - 25 = 40242013099 is a prime.
It is a super-2 number, since 2×402420131312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40242013098 and 40242013107.
It is not an unprimeable number, because it can be changed into a prime (40242013111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 394529490 + ... + 394529591.
It is an arithmetic number, because the mean of its divisors is an integer number (7101531738).
Almost surely, 240242013131 is an apocalyptic number.
40242013131 is a deficient number, since it is larger than the sum of its proper divisors (16570240773).
40242013131 is a wasteful number, since it uses less digits than its factorization.
40242013131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 789059101.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 40242013131 its reverse (13131024204), we get a palindrome (53373037335).
The spelling of 40242013131 in words is "forty billion, two hundred forty-two million, thirteen thousand, one hundred thirty-one".
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