4031113314023 has 2 divisors, whose sum is σ = 4031113314024. Its totient is φ = 4031113314022.

The previous prime is 4031113313977. The next prime is 4031113314061. The reversal of 4031113314023 is 3204133111304.

4031113314023 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4031113314023 - 2¹⁰ = 4031113312999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4031113313983 and 4031113314001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4031113314623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2015556657011 + 2015556657012.

It is an arithmetic number, because the mean of its divisors is an integer number (2015556657012).

Almost surely, 2^{4031113314023} is an apocalyptic number.

4031113314023 is a deficient number, since it is larger than the sum of its proper divisors (1).

4031113314023 is an equidigital number, since it uses as much as digits as its factorization.

4031113314023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 4031113314023 its reverse (3204133111304), we get a palindrome (7235246425327).

The spelling of 4031113314023 in words is "four trillion, thirty-one billion, one hundred thirteen million, three hundred fourteen thousand, twenty-three".