Base | Representation |
---|---|
bin | 10010010101001101010111… |
… | …10110101100100001011011 |
3 | 12021201201010110000112111120 |
4 | 21022212223312230201123 |
5 | 20240424214214040120 |
6 | 221422404240500323 |
7 | 11330245623426546 |
oct | 1112465366544133 |
9 | 167651113015446 |
10 | 40311151315035 |
11 | 1193195500a407 |
12 | 46306a301a6a3 |
13 | 196542c790323 |
14 | 9d50da63985d |
15 | 49d8bb3a9140 |
hex | 24a9abdac85b |
40311151315035 has 16 divisors (see below), whose sum is σ = 65314270487040. Its totient is φ = 21227137907040.
The previous prime is 40311151315003. The next prime is 40311151315069. The reversal of 40311151315035 is 53051315111304.
It is not a de Polignac number, because 40311151315035 - 25 = 40311151315003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40311151314987 and 40311151315005.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17008923421 + ... + 17008925790.
It is an arithmetic number, because the mean of its divisors is an integer number (4082141905440).
Almost surely, 240311151315035 is an apocalyptic number.
40311151315035 is a deficient number, since it is larger than the sum of its proper divisors (25003119172005).
40311151315035 is a wasteful number, since it uses less digits than its factorization.
40311151315035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34017849298.
The product of its (nonzero) digits is 13500, while the sum is 33.
Adding to 40311151315035 its reverse (53051315111304), we get a palindrome (93362466426339).
The spelling of 40311151315035 in words is "forty trillion, three hundred eleven billion, one hundred fifty-one million, three hundred fifteen thousand, thirty-five".
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