Base | Representation |
---|---|
bin | 100101100010111001… |
… | …110111001011011011 |
3 | 10212001112222110211112 |
4 | 211202321313023123 |
5 | 1130030343303201 |
6 | 30304153450535 |
7 | 2625006460244 |
oct | 454271671333 |
9 | 125045873745 |
10 | 40314041051 |
11 | 161082527a9 |
12 | 7991110a4b |
13 | 3a5615837b |
14 | 1d46197ccb |
15 | 10ae36b0bb |
hex | 962e772db |
40314041051 has 2 divisors, whose sum is σ = 40314041052. Its totient is φ = 40314041050.
The previous prime is 40314041041. The next prime is 40314041099. The reversal of 40314041051 is 15014041304.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40314041051 - 218 = 40313778907 is a prime.
It is not a weakly prime, because it can be changed into another prime (40314041041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20157020525 + 20157020526.
It is an arithmetic number, because the mean of its divisors is an integer number (20157020526).
Almost surely, 240314041051 is an apocalyptic number.
40314041051 is a deficient number, since it is larger than the sum of its proper divisors (1).
40314041051 is an equidigital number, since it uses as much as digits as its factorization.
40314041051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 40314041051 its reverse (15014041304), we get a palindrome (55328082355).
The spelling of 40314041051 in words is "forty billion, three hundred fourteen million, forty-one thousand, fifty-one".
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