Base | Representation |
---|---|
bin | 111010101010100011100… |
… | …010101110000000101101 |
3 | 112021101210210211010212222 |
4 | 322222203202232000231 |
5 | 1012022323304024323 |
6 | 12324002112205125 |
7 | 564155265022211 |
oct | 72524342560055 |
9 | 15241723733788 |
10 | 4031423111213 |
11 | 131479827a173 |
12 | 5513975397a5 |
13 | 233213c71874 |
14 | dd19c794941 |
15 | 6ecee9e19c8 |
hex | 3aaa38ae02d |
4031423111213 has 8 divisors (see below), whose sum is σ = 4064850832416. Its totient is φ = 3998035594800.
The previous prime is 4031423111113. The next prime is 4031423111239. The reversal of 4031423111213 is 3121113241304.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4031423111213 - 240 = 2931911483437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4031423111113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9849806 + ... + 10250927.
It is an arithmetic number, because the mean of its divisors is an integer number (508106354052).
Almost surely, 24031423111213 is an apocalyptic number.
It is an amenable number.
4031423111213 is a deficient number, since it is larger than the sum of its proper divisors (33427721203).
4031423111213 is a wasteful number, since it uses less digits than its factorization.
4031423111213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20102395.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 4031423111213 its reverse (3121113241304), we get a palindrome (7152536352517).
The spelling of 4031423111213 in words is "four trillion, thirty-one billion, four hundred twenty-three million, one hundred eleven thousand, two hundred thirteen".
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