Base | Representation |
---|---|
bin | 10010010101010110001111… |
… | …00010101111001100010001 |
3 | 12021202011102010212001111222 |
4 | 21022223013202233030101 |
5 | 20241013441131444213 |
6 | 221424512421214425 |
7 | 11330504565456344 |
oct | 1112530742571421 |
9 | 167664363761458 |
10 | 40315910812433 |
11 | 11933977690233 |
12 | 46315b0b61415 |
13 | 1965a0a853389 |
14 | 9d542c7b445b |
15 | 49da99155808 |
hex | 24aac78af311 |
40315910812433 has 2 divisors, whose sum is σ = 40315910812434. Its totient is φ = 40315910812432.
The previous prime is 40315910812399. The next prime is 40315910812559. The reversal of 40315910812433 is 33421801951304.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35086584632449 + 5229326179984 = 5923393^2 + 2286772^2 .
It is a cyclic number.
It is not a de Polignac number, because 40315910812433 - 26 = 40315910812369 is a prime.
It is not a weakly prime, because it can be changed into another prime (40315910812033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20157955406216 + 20157955406217.
It is an arithmetic number, because the mean of its divisors is an integer number (20157955406217).
Almost surely, 240315910812433 is an apocalyptic number.
It is an amenable number.
40315910812433 is a deficient number, since it is larger than the sum of its proper divisors (1).
40315910812433 is an equidigital number, since it uses as much as digits as its factorization.
40315910812433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 44.
The spelling of 40315910812433 in words is "forty trillion, three hundred fifteen billion, nine hundred ten million, eight hundred twelve thousand, four hundred thirty-three".
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