Base | Representation |
---|---|
bin | 111010101011001000011… |
… | …000100110000101001111 |
3 | 112021110101212220000220102 |
4 | 322223020120212011033 |
5 | 1012030110022324122 |
6 | 12324143312241315 |
7 | 564206511560042 |
oct | 72531030460517 |
9 | 15243355800812 |
10 | 4032041214287 |
11 | 1314a85172159 |
12 | 55152a54023b |
13 | 2332b2038328 |
14 | dd21a8d0c59 |
15 | 6ed38dd8492 |
hex | 3aac862614f |
4032041214287 has 2 divisors, whose sum is σ = 4032041214288. Its totient is φ = 4032041214286.
The previous prime is 4032041214283. The next prime is 4032041214349. The reversal of 4032041214287 is 7824121402304.
4032041214287 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4032041214287 - 22 = 4032041214283 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4032041214287.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4032041214283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016020607143 + 2016020607144.
It is an arithmetic number, because the mean of its divisors is an integer number (2016020607144).
Almost surely, 24032041214287 is an apocalyptic number.
4032041214287 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032041214287 is an equidigital number, since it uses as much as digits as its factorization.
4032041214287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 38.
The spelling of 4032041214287 in words is "four trillion, thirty-two billion, forty-one million, two hundred fourteen thousand, two hundred eighty-seven".
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