Base | Representation |
---|---|
bin | 111010101011011110000… |
… | …001110100111001010001 |
3 | 112021111100012011221202220 |
4 | 322223132001310321101 |
5 | 1012031331003010101 |
6 | 12324243323331253 |
7 | 564221511251316 |
oct | 72533601647121 |
9 | 15244305157686 |
10 | 4032404344401 |
11 | 1315151145194 |
12 | 551610080b29 |
13 | 23333c33aa14 |
14 | dd252c18d0d |
15 | 6ed5ac17636 |
hex | 3aade074e51 |
4032404344401 has 24 divisors (see below), whose sum is σ = 5908355286720. Its totient is φ = 2442889972992.
The previous prime is 4032404344387. The next prime is 4032404344403. The reversal of 4032404344401 is 1044434042304.
It is not a de Polignac number, because 4032404344401 - 213 = 4032404336209 is a prime.
It is a super-3 number, since 3×40324043444013 (a number of 39 digits) contains 333 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4032404344403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 80164261 + ... + 80214546.
It is an arithmetic number, because the mean of its divisors is an integer number (246181470280).
Almost surely, 24032404344401 is an apocalyptic number.
It is an amenable number.
4032404344401 is a deficient number, since it is larger than the sum of its proper divisors (1875950942319).
4032404344401 is a wasteful number, since it uses less digits than its factorization.
4032404344401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160378873 (or 160378856 counting only the distinct ones).
The product of its (nonzero) digits is 73728, while the sum is 33.
Adding to 4032404344401 its reverse (1044434042304), we get a palindrome (5076838386705).
The spelling of 4032404344401 in words is "four trillion, thirty-two billion, four hundred four million, three hundred forty-four thousand, four hundred one".
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