Base | Representation |
---|---|
bin | 111010101100000011100… |
… | …001010001000110110101 |
3 | 112021112222000202102012121 |
4 | 322230003201101012311 |
5 | 1012034123013442123 |
6 | 12324425553115541 |
7 | 564243216536554 |
oct | 72540341210665 |
9 | 15245860672177 |
10 | 4033033343413 |
11 | 13154441aa488 |
12 | 551766858bb1 |
13 | 23340c74aa99 |
14 | dd2b258dd9b |
15 | 6ed9606275d |
hex | 3ab038511b5 |
4033033343413 has 2 divisors, whose sum is σ = 4033033343414. Its totient is φ = 4033033343412.
The previous prime is 4033033343329. The next prime is 4033033343441. The reversal of 4033033343413 is 3143433303304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2266521217009 + 1766512126404 = 1505497^2 + 1329102^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4033033343413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4033033343113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016516671706 + 2016516671707.
It is an arithmetic number, because the mean of its divisors is an integer number (2016516671707).
Almost surely, 24033033343413 is an apocalyptic number.
It is an amenable number.
4033033343413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4033033343413 is an equidigital number, since it uses as much as digits as its factorization.
4033033343413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 34.
Adding to 4033033343413 its reverse (3143433303304), we get a palindrome (7176466646717).
The spelling of 4033033343413 in words is "four trillion, thirty-three billion, thirty-three million, three hundred forty-three thousand, four hundred thirteen".
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