Base | Representation |
---|---|
bin | 100101100011111011… |
… | …010111100101111011 |
3 | 10212002202021220120021 |
4 | 211203323113211323 |
5 | 1130044242310204 |
6 | 30310005511311 |
7 | 2625305440615 |
oct | 454373274573 |
9 | 125082256507 |
10 | 40331213179 |
11 | 16116a11444 |
12 | 7996a12537 |
13 | 3a5988b5aa |
14 | 1d48587db5 |
15 | 10b0b0e154 |
hex | 963ed797b |
40331213179 has 2 divisors, whose sum is σ = 40331213180. Its totient is φ = 40331213178.
The previous prime is 40331213147. The next prime is 40331213203. The reversal of 40331213179 is 97131213304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40331213179 - 25 = 40331213147 is a prime.
It is a super-3 number, since 3×403312131793 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (40331273179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20165606589 + 20165606590.
It is an arithmetic number, because the mean of its divisors is an integer number (20165606590).
Almost surely, 240331213179 is an apocalyptic number.
40331213179 is a deficient number, since it is larger than the sum of its proper divisors (1).
40331213179 is an equidigital number, since it uses as much as digits as its factorization.
40331213179 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13608, while the sum is 34.
The spelling of 40331213179 in words is "forty billion, three hundred thirty-one million, two hundred thirteen thousand, one hundred seventy-nine".
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