4033140411331 has 2 divisors, whose sum is σ = 4033140411332. Its totient is φ = 4033140411330.

The previous prime is 4033140411283. The next prime is 4033140411347. The reversal of 4033140411331 is 1331140413304.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4033140411331 - 2³⁷ = 3895701457859 is a prime.

It is a super-2 number, since 2×4033140411331² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4033140411331.

It is not a weakly prime, because it can be changed into another prime (4033140411371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016570205665 + 2016570205666.

It is an arithmetic number, because the mean of its divisors is an integer number (2016570205666).

Almost surely, 2^{4033140411331} is an apocalyptic number.

4033140411331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4033140411331 is an equidigital number, since it uses as much as digits as its factorization.

4033140411331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 4033140411331 its reverse (1331140413304), we get a palindrome (5364280824635).

The spelling of 4033140411331 in words is "four trillion, thirty-three billion, one hundred forty million, four hundred eleven thousand, three hundred thirty-one".