403321021134133 has 4 divisors (see below), whose sum is σ = 403321084274188. Its totient is φ = 403320957994080.

The previous prime is 403321021134079. The next prime is 403321021134181. The reversal of 403321021134133 is 331431120123304.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 394358314420849 + 8962706713284 = 19858457^2 + 2993778^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-403321021134133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 403321021134095 and 403321021134104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (403321021114133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20753016 + ... + 35175697.

It is an arithmetic number, because the mean of its divisors is an integer number (100830271068547).

Almost surely, 2^{403321021134133} is an apocalyptic number.

It is an amenable number.

403321021134133 is a deficient number, since it is larger than the sum of its proper divisors (63140055).

403321021134133 is an equidigital number, since it uses as much as digits as its factorization.

403321021134133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63140054.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 403321021134133 its reverse (331431120123304), we get a palindrome (734752141257437).

The spelling of 403321021134133 in words is "four hundred three trillion, three hundred twenty-one billion, twenty-one million, one hundred thirty-four thousand, one hundred thirty-three".