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40334512433 is a prime number
BaseRepresentation
bin100101100100000111…
…111101000100110001
310212002222111112021212
4211210013331010301
51130101113344213
630310204325505
72625345461465
oct454407750461
9125088445255
1040334512433
11161188651a6
127997b43895
133a5a475207
141d48ba64a5
1510b10619a8
hex9641fd131

40334512433 has 2 divisors, whose sum is σ = 40334512434. Its totient is φ = 40334512432.

The previous prime is 40334512429. The next prime is 40334512451. The reversal of 40334512433 is 33421543304.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34986954304 + 5347558129 = 187048^2 + 73127^2 .

It is a cyclic number.

It is not a de Polignac number, because 40334512433 - 22 = 40334512429 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40334512433.

It is not a weakly prime, because it can be changed into another prime (40334512403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20167256216 + 20167256217.

It is an arithmetic number, because the mean of its divisors is an integer number (20167256217).

Almost surely, 240334512433 is an apocalyptic number.

It is an amenable number.

40334512433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40334512433 is an equidigital number, since it uses as much as digits as its factorization.

40334512433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 32.

The spelling of 40334512433 in words is "forty billion, three hundred thirty-four million, five hundred twelve thousand, four hundred thirty-three".