4034043313 has 2 divisors, whose sum is σ = 4034043314. Its totient is φ = 4034043312.

The previous prime is 4034043287. The next prime is 4034043331. The reversal of 4034043313 is 3133404304.

4034043313 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (4034043331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4008409344 + 25633969 = 63312^2 + 5063^2 .

It is a cyclic number.

It is not a de Polignac number, because 4034043313 - 2¹³ = 4034035121 is a prime.

It is a super-3 number, since 3×4034043313³ (a number of 30 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4034043353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017021656 + 2017021657.

It is an arithmetic number, because the mean of its divisors is an integer number (2017021657).

Almost surely, 2^4034043313 is an apocalyptic number.

It is an amenable number.

4034043313 is a deficient number, since it is larger than the sum of its proper divisors (1).

4034043313 is an equidigital number, since it uses as much as digits as its factorization.

4034043313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 25.

The square root of 4034043313 is about 63514.1190051472. The cubic root of 4034043313 is about 1591.8917021490.

Adding to 4034043313 its reverse (3133404304), we get a palindrome (7167447617).

The spelling of 4034043313 in words is "four billion, thirty-four million, forty-three thousand, three hundred thirteen".