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4034102232013 = 7576300318859
BaseRepresentation
bin111010101101000011001…
…110110000001111001101
3112021122201112001120201021
4322231003032300033031
51012043320132411023
612325124015114141
7564311546125060
oct72550316601715
915248645046637
104034102232013
1113159425a5297
12551a04812951
13233550027949
14dd3745108d7
156ee09d0035d
hex3ab433b03cd

4034102232013 has 4 divisors (see below), whose sum is σ = 4610402550880. Its totient is φ = 3457801913148.

The previous prime is 4034102232007. The next prime is 4034102232029. The reversal of 4034102232013 is 3102322014304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4034102232013 - 225 = 4034068677581 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4034102232073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 288150159423 + ... + 288150159436.

It is an arithmetic number, because the mean of its divisors is an integer number (1152600637720).

Almost surely, 24034102232013 is an apocalyptic number.

It is an amenable number.

4034102232013 is a deficient number, since it is larger than the sum of its proper divisors (576300318867).

4034102232013 is an equidigital number, since it uses as much as digits as its factorization.

4034102232013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 576300318866.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 4034102232013 its reverse (3102322014304), we get a palindrome (7136424246317).

The spelling of 4034102232013 in words is "four trillion, thirty-four billion, one hundred two million, two hundred thirty-two thousand, thirteen".

Divisors: 1 7 576300318859 4034102232013